What is the solution for (dy)/(dx)+ycos(x)=sin(x)cos(x) ?

The solution for (dy)/(dx)+ycos(x)=sin(x)cos(x) is y=sin(x)-1+(c_{1})/(e^{sin(x))}

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(dy)/(dx)+ycos(x)=sin(x)cos(x)

\frac{d y}{d x} + y cos (x) = sin (x) cos (x)

y = sin (x) - 1 + \frac{c _{1}}{e ^{s i n (x)}}

Solution steps

\frac{d y}{d x} + y cos (x) = sin (x) cos (x)

Solve linear ODE:

y = sin (x) - 1 + \frac{c _{1}}{e ^{s i n (x)}}

y = sin (x) - 1 + \frac{c _{1}}{e ^{s i n (x)}}

- csc (x) - sin (x)

- 6 t^{3}

f (x) = x^{3} + 6 x^{2} + x

y^{^{''}} + 2 y^{^{'}} + 10 y = 3 e^{t} + 1

\int 2050 - 18 x - 4 x^{2} d x

What is the solution for (dy)/(dx)+ycos(x)=sin(x)cos(x) ?
The solution for (dy)/(dx)+ycos(x)=sin(x)cos(x) is y=sin(x)-1+(c_{1})/(e^{sin(x))}