What is the integral of 1/(1-sin^2(x)) ?

The integral of 1/(1-sin^2(x)) is tan(x)+C

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integral of 1/(1-sin^2(x))

\int \frac{1}{1 - sin ^{2} ( x )} d x

tan (x) + C

Solution steps

\int \frac{1}{1 - sin ^{2} ( x )} d x

Rewrite using trig identities

= \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= tan (x)

Add a constant to the solution

= tan (x) + C

\int (x^{1.7} + 7 x^{2.5}) d x

x \to 2 + lim (\frac{x ^{2}}{x - 2})

f (t) = \frac{1}{2 t + 3}

n = 0 \sum \infty 6 (- 1)^{n} n x^{n}

sin (2 θ) cos (θ)

What is the integral of 1/(1-sin^2(x)) ?
The integral of 1/(1-sin^2(x)) is tan(x)+C