What is the solution for (x-1)y^'+(x-2)y=0 ?

The solution for (x-1)y^'+(x-2)y=0 is y=e^{-x+c_{1}}x-e^{-x+c_{1}}

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(x-1)y^'+(x-2)y=0

(x - 1) y^{^{'}} + (x - 2) y = 0

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

Solution steps

(x - 1) y^{'} (x) + (x - 2) y = 0

Solve separable ODE:

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

\frac{d}{d x} (- 2 cos (x))

y ln (x) ln (y) d x + d y = 0

\int \frac{2 ^{x}}{3 ^{x}} d x

\frac{d}{d x} (6 x cos (x^{2}))

\int_{1}^{e} \frac{x ^{2} + 1}{x} d x

What is the solution for (x-1)y^'+(x-2)y=0 ?
The solution for (x-1)y^'+(x-2)y=0 is y=e^{-x+c_{1}}x-e^{-x+c_{1}}