What is the derivative of (2x+7^2) ?

The derivative of (2x+7^2) is 4(2x+7)

What is the first derivative of (2x+7^2) ?

The first derivative of (2x+7^2) is 4(2x+7)

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\frac{d}{d x} ((2 x + 7)^{2})

4 (2 x + 7)

Solution steps

\frac{d}{d x} ((2 x + 7)^{2})

Apply the chain rule:

2 (2 x + 7) \frac{d}{d x} (2 x + 7)

= 2 (2 x + 7) \frac{d}{d x} (2 x + 7)

\frac{d}{d x} (2 x + 7) = 2

= 2 (2 x + 7) \cdot 2

Simplify

= 4 (2 x + 7)

\frac{d}{d x} y - y = 3

y = \frac{3}{x}, y = 8 x, y = \frac{1}{8} x

\frac{d}{d x} (x^{3} + 8 x)

\frac{1}{1 - x ^{2}}, 0

y = 2 x, y = x, x = 0, x = 4

What is the derivative of (2x+7^2) ?
The derivative of (2x+7^2) is 4(2x+7)
What is the first derivative of (2x+7^2) ?
The first derivative of (2x+7^2) is 4(2x+7)