What is area y=2sqrt(x),y=sqrt(x),x=0,x=4 ?

The answer to area y=2sqrt(x),y=sqrt(x),x=0,x=4 is 16/3

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area y=2sqrt(x),y=sqrt(x),x=0,x=4

area

y = 2 x, y = x, x = 0, x = 4

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x d x

Solve

\int_{0}^{4} x d x : \frac{16}{3}

The area is:

= \frac{16}{3}

f (x) = 5 - 2 x^{2}, (1, 3)

\frac{d}{d x} (7 e^{- x} - 8 e^{- 7 x})

f (x) = \frac{( x + 3 )}{2 x + 1}, at x = - 1

x \to 2 lim (\frac{1}{∣ x - 2 ∣})

\int \frac{7 x ^{3} - 1}{x ^{2}} d x

What is area y=2sqrt(x),y=sqrt(x),x=0,x=4 ?
The answer to area y=2sqrt(x),y=sqrt(x),x=0,x=4 is 16/3