What is the integral from 2 to infinity of ye^{-7y} ?

The integral from 2 to infinity of ye^{-7y} is (15)/(49e^{14)}

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integral from 2 to infinity of ye^{-7y}

\int_{2}^{\infty} y e^{- 7 y} d y

\frac{15}{49 e ^{14}}

Decimal Notation

2.5455 E - 7

Solution steps

\int_{2}^{\infty} y e^{- 7 y} d y

Compute the indefinite integral:

\int y e^{- 7 y} d y = \frac{1}{49} (- 7 e^{- 7 y} y - e^{- 7 y}) + C

Compute the boundaries:

\int_{2}^{\infty} y e^{- 7 y} d y = 0 - (- \frac{15}{49 e ^{14}})

= 0 - (- \frac{15}{49 e ^{14}})

Simplify

= \frac{15}{49 e ^{14}}

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What is the integral from 2 to infinity of ye^{-7y} ?
The integral from 2 to infinity of ye^{-7y} is (15)/(49e^{14)}