What is the d/(dθ)(14sin(θ)) ?

The d/(dθ)(14sin(θ)) is 14cos(θ)

What is the first d/(dθ)(14sin(θ)) ?

The first d/(dθ)(14sin(θ)) is 14cos(θ)

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\frac{d}{d θ} (14 sin (θ))

14 cos (θ)

Solution steps

\frac{d}{d θ} (14 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 14 cos (θ)

\frac{d y}{d x} = 2 x e^{- y}

\int \frac{1}{a - b y} d y

y^{^{'}} = y (7 - y) - \frac{49}{4}, y (0) = a

y^{^{'}} = \frac{( 3 x ^{4} + y ^{4} )}{x y ^{3}}

\frac{d}{d x} (x^{3} - cos (x))