What is the limit as x approaches 2 of (x^2+x)/(x+3) ?

The limit as x approaches 2 of (x^2+x)/(x+3) is 6/5

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limit as x approaches 2 of (x^2+x)/(x+3)

x \to 2 lim (\frac{x ^{2} + x}{x + 3})

\frac{6}{5}

Decimal Notation

1.2

Solution steps

x \to 2 lim (\frac{x ^{2} + x}{x + 3})

Plug in the value

x = 2

= \frac{2 ^{2} + 2}{2 + 3}

Simplify

= \frac{6}{5}

x \to 1 lim (r (t))

\frac{x ^{2}}{ln ( 3 ^{x} )}

\int x ln (10 x) d x

\int sec (x) tan (x) - 2 e^{x} d x

\int sin^{5} (2 θ) d θ

What is the limit as x approaches 2 of (x^2+x)/(x+3) ?
The limit as x approaches 2 of (x^2+x)/(x+3) is 6/5