What is the derivative of f(x)=ln(x^2+2) ?

The derivative of f(x)=ln(x^2+2) is (2x)/(x^2+2)

What is the first derivative of f(x)=ln(x^2+2) ?

The first derivative of f(x)=ln(x^2+2) is (2x)/(x^2+2)

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derivative of

f (x) = ln (x^{2} + 2)

\frac{2 x}{x ^{2} + 2}

Solution steps

\frac{d}{d x} (ln (x^{2} + 2))

Apply the chain rule:

\frac{1}{x ^{2} + 2} \frac{d}{d x} (x^{2} + 2)

= \frac{1}{x ^{2} + 2} \frac{d}{d x} (x^{2} + 2)

\frac{d}{d x} (x^{2} + 2) = 2 x

= \frac{1}{x ^{2} + 2} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 2} \cdot 2 x : \frac{2 x}{x ^{2} + 2}

= \frac{2 x}{x ^{2} + 2}

y^{^{''}} + 9 y^{^{'}} + 18 y = 2050 e^{2 t} cos (10 t)

\int_{- 3}^{1} x + 3 d x

y = 2 x^{3} - 3 x + 1, (1, 0)

\frac{d}{d x} (- x sin (x) + cos (x))

\int \frac{1}{3 + cos ( x )} d x

What is the derivative of f(x)=ln(x^2+2) ?
The derivative of f(x)=ln(x^2+2) is (2x)/(x^2+2)
What is the first derivative of f(x)=ln(x^2+2) ?
The first derivative of f(x)=ln(x^2+2) is (2x)/(x^2+2)