What is the derivative of y=3^x ?

The derivative of y=3^x is 3^xln(3)

What is the first derivative of y=3^x ?

The first derivative of y=3^x is 3^xln(3)

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derivative of

y = 3^{x}

3^{x} ln (3)

Solution steps

\frac{d}{d x} (3^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 3^{x} ln (3)

\frac{d y}{d x} = \frac{x y + y + x + 1}{x y + 2 x - y - 2}

\frac{d}{d x} (\frac{x - 4}{- x ^{2} + 4})

\frac{( 2 s + 1 )}{s ^{2} + 2 s + 5}

\int (x^{2} ln (x)) d x

\frac{\partial}{\partial x} (cos^{2} (3 x))

What is the derivative of y=3^x ?
The derivative of y=3^x is 3^xln(3)
What is the first derivative of y=3^x ?
The first derivative of y=3^x is 3^xln(3)