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Popular >

area y=x^2-x,y=0

Solution

area

y = x^{2} - x, y = 0

Solution

\frac{1}{6}

+1

Decimal Notation

0.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{2} - x d x

Solve

\int_{0}^{1} x^{2} - x d x : \frac{1}{6}

The area is:

= \frac{1}{6}

Popular Examples

inverse oflaplace (2s+9)/(s^2+4s+40)inverse laplace

\frac{2 s + 9}{s ^{2} + 4 s + 40}

(\partial)/(\partial t)(t/(c^2t^2-x^2))

\frac{\partial}{\partial t} (\frac{t}{c ^{2} t ^{2} - x ^{2}})

y^{''}+12y^'+36=0

y^{^{''}} + 12 y^{^{'}} + 36 = 0

(\partial)/(\partial x)(ye^x+xln(z))

\frac{\partial}{\partial x} (y e^{x} + x ln (z))

t y^{^{'}} = 4 t^{2} - 2 y

Frequently Asked Questions (FAQ)

What is area y=x^2-x,y=0 ?
The answer to area y=x^2-x,y=0 is 1/6