What is the integral from 2 to infinity of 4x^{-2} ?

The integral from 2 to infinity of 4x^{-2} is 2

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integral from 2 to infinity of 4x^{-2}

\int_{2}^{\infty} 4 x^{- 2} d x

2

Solution steps

\int_{2}^{\infty} 4 x^{- 2} d x

Compute the indefinite integral:

\int 4 x^{- 2} d x = - \frac{4}{x} + C

Compute the boundaries:

\int_{2}^{\infty} 4 x^{- 2} d x = 0 - (- 2)

= 0 - (- 2)

Simplify

= 2

\frac{\partial}{\partial x} (y^{6} cos (2 x) \cdot 2)

\int 15 x e^{- 8 x^{2}} d x

y^{^{''}} - 4 y^{^{'}} = - 4 y

5 x^{2} + 9 y^{2} = 36, (6, 4)

\frac{d}{d x} (\frac{2 x}{ln ( x )})

What is the integral from 2 to infinity of 4x^{-2} ?
The integral from 2 to infinity of 4x^{-2} is 2