What is (\partial)/(\partial x)(2x+2y+z) ?

The answer to (\partial)/(\partial x)(2x+2y+z) is 2

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(\partial)/(\partial x)(2x+2y+z)

\frac{\partial}{\partial x} (2 x + 2 y + z)

2

Solution steps

\frac{\partial}{\partial x} (2 x + 2 y + z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (z)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (z) = 0

= 2 + 0 + 0

Simplify

= 2

\frac{d}{d x} (x^{3} y^{4})

f (x) = \frac{5 x - 9}{x + 1}, at x = 0

f (x) = \frac{x ^{2}}{x - 1}

\int 4 x 1 - x^{2} d x

\frac{d}{d x} (\frac{24}{( 1 - x ) ^{4}})

What is (\partial)/(\partial x)(2x+2y+z) ?
The answer to (\partial)/(\partial x)(2x+2y+z) is 2