What is the solution for xy^'+2y= 2/(x^2)+1 ?

The solution for xy^'+2y= 2/(x^2)+1 is y=(2ln(x))/(x^2)+1/2+(c_{1})/(x^2)

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xy^'+2y= 2/(x^2)+1

x y^{^{'}} + 2 y = \frac{2}{x ^{2}} + 1

y = \frac{2 ln ( x )}{x ^{2}} + \frac{1}{2} + \frac{c _{1}}{x ^{2}}

Solution steps

x y^{'} (x) + 2 y = \frac{2}{x ^{2}} + 1

Solve linear ODE:

y = \frac{2 ln ( x )}{x ^{2}} + \frac{1}{2} + \frac{c _{1}}{x ^{2}}

y = \frac{2 ln ( x )}{x ^{2}} + \frac{1}{2} + \frac{c _{1}}{x ^{2}}

\int x^{3} e x^{2} d x

\int (n x) \frac{1 - n}{n} d x

\frac{\partial}{\partial x} (x^{2} z)

\frac{d}{d x} (9 sin^{3} (x))

n = 1 \sum \infty \frac{n ^{3}}{3 n ^{2}}

What is the solution for xy^'+2y= 2/(x^2)+1 ?
The solution for xy^'+2y= 2/(x^2)+1 is y=(2ln(x))/(x^2)+1/2+(c_{1})/(x^2)