What is the derivative of 9sin^3(x) ?

The derivative of 9sin^3(x) is 27sin^2(x)cos(x)

What is the first derivative of 9sin^3(x) ?

The first derivative of 9sin^3(x) is 27sin^2(x)cos(x)

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\frac{d}{d x} (9 sin^{3} (x))

27 sin^{2} (x) cos (x)

Solution steps

\frac{d}{d x} (9 sin^{3} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (sin^{3} (x))

Apply the chain rule:

3 (sin (x))^{2} \frac{d}{d x} (sin (x))

= 3 (sin (x))^{2} \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= 9 \cdot 3 (sin (x))^{2} cos (x)

Simplify

= 27 sin^{2} (x) cos (x)

n = 1 \sum \infty \frac{n ^{3}}{3 n ^{2}}

\frac{d}{d x} (x (4 - x))

\int 3 cos (θ) d θ

\frac{d}{d x} (920 + 2 x - 0.2 x^{2} + 0.7 x^{3})

\frac{d}{d x} (- 3 x^{- 2})

What is the derivative of 9sin^3(x) ?
The derivative of 9sin^3(x) is 27sin^2(x)cos(x)
What is the first derivative of 9sin^3(x) ?
The first derivative of 9sin^3(x) is 27sin^2(x)cos(x)