What is the derivative of arccos(3x) ?

The derivative of arccos(3x) is -3/(sqrt(1-9x^2))

What is the first derivative of arccos(3x) ?

The first derivative of arccos(3x) is -3/(sqrt(1-9x^2))

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derivative of

arccos (3 x)

- \frac{3}{1 - 9 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (3 x))

Apply the chain rule:

- \frac{1}{1 - ( 3 x ) ^{2}} \frac{d}{d x} (3 x)

= - \frac{1}{1 - ( 3 x ) ^{2}} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - \frac{1}{1 - ( 3 x ) ^{2}} \cdot 3

Simplify

- \frac{1}{1 - ( 3 x ) ^{2}} \cdot 3 : - \frac{3}{1 - 9 x ^{2}}

= - \frac{3}{1 - 9 x ^{2}}

\int u sin (u) d u

x y + y^{^{'}} = 2 x, y (0) = 5

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = 4 x^{2}

\int \frac{2 x ^{2}}{x ^{2} + 8} d x

\int 3 x^{3} - 2 x^{2} + 8 x - 6 d x

What is the derivative of arccos(3x) ?
The derivative of arccos(3x) is -3/(sqrt(1-9x^2))
What is the first derivative of arccos(3x) ?
The first derivative of arccos(3x) is -3/(sqrt(1-9x^2))