What is the derivative of 2x^8e^x ?

The derivative of 2x^8e^x is 2(8x^7e^x+e^xx^8)

What is the first derivative of 2x^8e^x ?

The first derivative of 2x^8e^x is 2(8x^7e^x+e^xx^8)

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derivative of

2 x^{8} e^{x}

2 (8 x^{7} e^{x} + e^{x} x^{8})

Solution steps

\frac{d}{d x} (2 x^{8} e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{8} e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{8}, g = e^{x}

= 2 (\frac{d}{d x} (x^{8}) e^{x} + \frac{d}{d x} (e^{x}) x^{8})

\frac{d}{d x} (x^{8}) = 8 x^{7}

\frac{d}{d x} (e^{x}) = e^{x}

= 2 (8 x^{7} e^{x} + e^{x} x^{8})

\int \frac{1}{4 x} d x

\frac{d}{d x} (4 x^{3} + 5 x)

\frac{d}{d x} (arctan (\frac{5}{x}))

\frac{x ^{2} + 2 x - 2}{( x + 1 ) ^{2}}

\frac{\partial}{\partial z} (x z e^{yz})

What is the derivative of 2x^8e^x ?
The derivative of 2x^8e^x is 2(8x^7e^x+e^xx^8)
What is the first derivative of 2x^8e^x ?
The first derivative of 2x^8e^x is 2(8x^7e^x+e^xx^8)