What is the solution for xy^'+y=3xsqrt(y) ?

The solution for xy^'+y=3xsqrt(y) is y=x^2+2c_{1}sqrt(x)+(c_{1}^2)/x

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xy^'+y=3xsqrt(y)

x y^{^{'}} + y = 3 x y

y = x^{2} + 2 c_{1} x + \frac{c _{1}^{2}}{x}

Solution steps

x y^{'} (x) + y = 3 x y

Solve Bernoulli ODE:

y = x^{2} + 2 c_{1} x + \frac{c _{1}^{2}}{x}

y = x^{2} + 2 c_{1} x + \frac{c _{1}^{2}}{x}

\int_{1}^{10} \frac{1}{x ^{2}} d x

x^{2} (sin (x))

\frac{d y}{d x} = y \cdot (\frac{1}{x} - y)

\frac{\partial}{\partial u} (\frac{v}{u})

\frac{d}{d x} (ln (\frac{9 - x}{5 + x}))

What is the solution for xy^'+y=3xsqrt(y) ?
The solution for xy^'+y=3xsqrt(y) is y=x^2+2c_{1}sqrt(x)+(c_{1}^2)/x