What is the derivative of sex+cos(x) ?

The derivative of sex+cos(x) is es-sin(x)

What is the first derivative of sex+cos(x) ?

The first derivative of sex+cos(x) is es-sin(x)

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\frac{d}{d x} (se x + cos (x))

es - sin (x)

Solution steps

\frac{d}{d x} (se x + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (se x) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (se x) = es

\frac{d}{d x} (cos (x)) = - sin (x)

= es - sin (x)

\int 2 x (x^{2} + 1)^{6} d x

\frac{d}{d x} (cos (e^{- 5 x^{5}}))

\int \frac{8 + tan ( x )}{1 - sin ^{2} ( x )} d x

\int \frac{4}{t ^{2}} d t

22 x^{3}

What is the derivative of sex+cos(x) ?
The derivative of sex+cos(x) is es-sin(x)
What is the first derivative of sex+cos(x) ?
The first derivative of sex+cos(x) is es-sin(x)