What is (\partial)/(\partial x)(4y^x) ?

The answer to (\partial)/(\partial x)(4y^x) is 4y^xln(y)

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(\partial)/(\partial x)(4y^x)

\frac{\partial}{\partial x} (4 y^{x})

4 y^{x} ln (y)

Solution steps

\frac{\partial}{\partial x} (4 y^{x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (y^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4 y^{x} ln (y)

9 x - 9 x

\frac{d}{d x} ((x^{2} + y^{2}) sin (\frac{1}{x ^{2} + y ^{2}}))

\int sin (x) in (cos (x)) d x

f (x) = 8 sec (x) tan (x)

f (x) = x^{2} + 1, (0, 1)

What is (\partial)/(\partial x)(4y^x) ?
The answer to (\partial)/(\partial x)(4y^x) is 4y^xln(y)