What is the derivative of-arcsin(1/x+e^2) ?

The derivative of-arcsin(1/x+e^2) is 1/(xsqrt(x^2-1))

What is the first derivative of-arcsin(1/x+e^2) ?

The first derivative of-arcsin(1/x+e^2) is 1/(xsqrt(x^2-1))

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\frac{d}{d x} (- arcsin (\frac{1}{x}) + e^{2})

\frac{1}{x x ^{2} - 1}

Solution steps

\frac{d}{d x} (- arcsin (\frac{1}{x}) + e^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (arcsin (\frac{1}{x})) + \frac{d}{d x} (e^{2})

\frac{d}{d x} (arcsin (\frac{1}{x})) = - \frac{1}{x x ^{2} - 1}

\frac{d}{d x} (e^{2}) = 0

= - (- \frac{1}{x x ^{2} - 1}) + 0

Simplify

= \frac{1}{x x ^{2} - 1}

f (x) = [ln (x)]^{x}

y^{'} = 0.0015 y (2100 - y)

\frac{d y}{d x} = x^{\frac{3}{2}}

\int - \frac{1}{n ^{2}} cos (n t) d t

\frac{\partial}{\partial x} (x^{3} cos (x y))

What is the derivative of-arcsin(1/x+e^2) ?
The derivative of-arcsin(1/x+e^2) is 1/(xsqrt(x^2-1))
What is the first derivative of-arcsin(1/x+e^2) ?
The first derivative of-arcsin(1/x+e^2) is 1/(xsqrt(x^2-1))