What is (\partial)/(\partial x)(2xy^2) ?

The answer to (\partial)/(\partial x)(2xy^2) is 2y^2

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(\partial)/(\partial x)(2xy^2)

\frac{\partial}{\partial x} (2 x y^{2})

2 y^{2}

Solution steps

\frac{\partial}{\partial x} (2 x y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y^{2} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 2 y^{2} \cdot 1

Simplify

= 2 y^{2}

\frac{\partial}{\partial x} (3 x^{2} - 6 x y + y^{3} - 9 y + 5)

\frac{d}{d x} (arcsin (\frac{2 x}{1 + x ^{2}}))

\frac{d}{d t} (- 3 e^{- 3 t})

4 sin (x + \frac{π}{3}) - 1

What is (\partial)/(\partial x)(2xy^2) ?
The answer to (\partial)/(\partial x)(2xy^2) is 2y^2