What is the derivative of f(x)=x^3-2 ?

The derivative of f(x)=x^3-2 is 3x^2

What is the first derivative of f(x)=x^3-2 ?

The first derivative of f(x)=x^3-2 is 3x^2

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derivative of

f (x) = x^{3} - 2

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2) = 0

= 3 x^{2} - 0

Simplify

= 3 x^{2}

\frac{d}{d x} (lo g_{4} (x^{2} - 7 x))

\int x^{2} + 9 d x

y^{^{'}} - 2 t y = 9 t^{2} e^{t^{2}}

\frac{\partial}{\partial x} (x sin (x^{2} y))

y^{8} - \frac{x ^{4} y ^{9} + 4}{x ^{5} + 4 y ^{^{'}}} = 0

What is the derivative of f(x)=x^3-2 ?
The derivative of f(x)=x^3-2 is 3x^2
What is the first derivative of f(x)=x^3-2 ?
The first derivative of f(x)=x^3-2 is 3x^2