What is the solution for y^'-2ty=9t^2e^{t^2} ?

The solution for y^'-2ty=9t^2e^{t^2} is y=3e^{t^2}t^3+c_{1}e^{t^2}

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y^'-2ty=9t^2e^{t^2}

y^{^{'}} - 2 t y = 9 t^{2} e^{t^{2}}

y = 3 e^{t^{2}} t^{3} + c_{1} e^{t^{2}}

Solution steps

y^{'} (t) - 2 t y = 9 t^{2} e^{t^{2}}

Solve linear ODE:

y = 3 e^{t^{2}} t^{3} + c_{1} e^{t^{2}}

y = 3 e^{t^{2}} t^{3} + c_{1} e^{t^{2}}

\frac{\partial}{\partial x} (x sin (x^{2} y))

y^{8} - \frac{x ^{4} y ^{9} + 4}{x ^{5} + 4 y ^{^{'}}} = 0

\int_{0}^{1} 1 + 4 x^{2} d x

\frac{3 x - 2}{2 x + 1}

f (x) = e^{t a n (θ)}

What is the solution for y^'-2ty=9t^2e^{t^2} ?
The solution for y^'-2ty=9t^2e^{t^2} is y=3e^{t^2}t^3+c_{1}e^{t^2}