What is area f(x)=cos(x),sin(x),0,(2pi)/4 ?

The answer to area f(x)=cos(x),sin(x),0,(2pi)/4 is 2sqrt(2)-2

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area f(x)=cos(x),sin(x),0,(2pi)/4

area

f (x) = cos (x), sin (x), 0, \frac{2 π}{4}

22 - 2

Decimal Notation

0.82842 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{2 π}{4}} ∣ cos (x) - sin (x) ∣ d x

Solve

\int_{0}^{\frac{2 π}{4}} ∣ cos (x) - sin (x) ∣ d x : 22 - 2

The area is:

= 22 - 2

\int x^{6} sin (4 x) d x

f (x) = x + x

(t^{- 1})^{^{'}}

f (x) = 5 x^{2} - x^{3}

\frac{\partial}{\partial x} (e^{s i n (y)})

What is area f(x)=cos(x),sin(x),0,(2pi)/4 ?
The answer to area f(x)=cos(x),sin(x),0,(2pi)/4 is 2sqrt(2)-2