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Popular >

(t^{-1})^'

Solution

(t^{- 1})^{^{'}}

Solution

- \frac{1}{t ^{2}}

Solution steps

(t^{- 1})^{'}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot t^{- 1 - 1}

Simplify

- 1 \cdot t^{- 1 - 1} : - \frac{1}{t ^{2}}

= - \frac{1}{t ^{2}}

Popular Examples

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f (x) = 5 x^{2} - x^{3}

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taylor cos(x^2)*2x taylor

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\int 4 (6 x + 1)^{5} d x

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f (x) = 3 x^{3} + 3 x^{2} + 3 x

Frequently Asked Questions (FAQ)

What is the (t^{-1})^' ?
The (t^{-1})^' is -1/(t^2)
What is the first (t^{-1})^' ?
The first (t^{-1})^' is -1/(t^2)