What is the derivative of f(x)=3x^3+3x^2+3x ?

The derivative of f(x)=3x^3+3x^2+3x is 9x^2+6x+3

What is the first derivative of f(x)=3x^3+3x^2+3x ?

The first derivative of f(x)=3x^3+3x^2+3x is 9x^2+6x+3

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derivative of

f (x) = 3 x^{3} + 3 x^{2} + 3 x

9 x^{2} + 6 x + 3

Solution steps

\frac{d}{d x} (3 x^{3} + 3 x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

= 9 x^{2} + 6 x + 3

\int_{0}^{1} x^{4} e^{8 x} d x

f (x) = (x - 2) (2 x + 3)

(1 - x^{2}) y^{^{''}} + 2 x y^{^{'}} - 2 y = 0

f (x) = ln (x^{3} - 5 x^{2} + 3 x - 1)

f (t) = 3 t^{3} - \frac{2}{t ^{2}}

What is the derivative of f(x)=3x^3+3x^2+3x ?
The derivative of f(x)=3x^3+3x^2+3x is 9x^2+6x+3
What is the first derivative of f(x)=3x^3+3x^2+3x ?
The first derivative of f(x)=3x^3+3x^2+3x is 9x^2+6x+3