What is the derivative of f(t)=3t^3-2/(t^2) ?

The derivative of f(t)=3t^3-2/(t^2) is 9t^2+4/(t^3)

What is the first derivative of f(t)=3t^3-2/(t^2) ?

The first derivative of f(t)=3t^3-2/(t^2) is 9t^2+4/(t^3)

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derivative of

f (t) = 3 t^{3} - \frac{2}{t ^{2}}

9 t^{2} + \frac{4}{t ^{3}}

Solution steps

\frac{d}{d t} (3 t^{3} - \frac{2}{t ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3 t^{3}) - \frac{d}{d t} (\frac{2}{t ^{2}})

\frac{d}{d t} (3 t^{3}) = 9 t^{2}

\frac{d}{d t} (\frac{2}{t ^{2}}) = - \frac{4}{t ^{3}}

= 9 t^{2} - (- \frac{4}{t ^{3}})

Simplify

= 9 t^{2} + \frac{4}{t ^{3}}

x \to 0 + lim (\frac{1}{2 x ^{2}})

3 + 5 x

\frac{d}{d x} (x + y z)

1.5 - 1.5 e^{- t}

What is the derivative of f(t)=3t^3-2/(t^2) ?
The derivative of f(t)=3t^3-2/(t^2) is 9t^2+4/(t^3)
What is the first derivative of f(t)=3t^3-2/(t^2) ?
The first derivative of f(t)=3t^3-2/(t^2) is 9t^2+4/(t^3)