What is the tangent of f(x)=4x-3sqrt(x),(4,10) ?

The tangent of f(x)=4x-3sqrt(x),(4,10) is y= 13/4 x-3

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tangent of f(x)=4x-3sqrt(x),(4,10)

tangent of

f (x) = 4 x - 3 x, (4, 10)

y = \frac{13}{4} x - 3

Solution steps

Find the slope of

f (x) = 4 x - 3 x : \frac{df ( x )}{d x} = 4 - \frac{3}{2 x}

Compute the slope of

f (x) = 4 x - 3 x

(4, 10) : m = \frac{13}{4}

Find the line with slope m=

\frac{13}{4}

and passing through

(4, 10) : y = \frac{13}{4} x - 3

y = \frac{13}{4} x - 3

\frac{d}{d x} (e^{x + l n (x)})

x \to \infty lim ((- 2)^{x})

\frac{\partial}{\partial x} (2 π x y + π x^{2})

\frac{\partial}{\partial x} (e^{- 3 x})

cos (y) + (1 + e^{- x}) sin (y) \frac{d y}{d x} = 0

What is the tangent of f(x)=4x-3sqrt(x),(4,10) ?
The tangent of f(x)=4x-3sqrt(x),(4,10) is y= 13/4 x-3