What is the sum from k=1 to infinity of 1/(k+2) ?

The sum from k=1 to infinity of 1/(k+2) is diverges

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sum from k=1 to infinity of 1/(k+2)

k = 1 \sum \infty \frac{1}{k + 2}

diverges

Solution steps

k = 1 \sum \infty \frac{1}{k + 2}

Apply Series Integral Test:

diverges

= diverges

1 + 3 x

e^{1 - 2 t}

\frac{d}{d x} (\frac{2 x ^{3} - 6 π ^{2}}{x ^{5}})

\int π cos (\frac{n x}{2}) d x

x \to 0 lim (- 7)

What is the sum from k=1 to infinity of 1/(k+2) ?
The sum from k=1 to infinity of 1/(k+2) is diverges