What is the derivative of 9e^{-2x} ?

The derivative of 9e^{-2x} is -18e^{-2x}

What is the first derivative of 9e^{-2x} ?

The first derivative of 9e^{-2x} is -18e^{-2x}

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\frac{d}{d x} (9 e^{- 2 x})

- 18 e^{- 2 x}

Solution steps

\frac{d}{d x} (9 e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= 9 e^{- 2 x} (- 2)

Simplify

= - 18 e^{- 2 x}

\int 4 + e^{x} d x

\frac{d}{d x} (\frac{1}{16} x^{4})

\int 6 sec^{4} (x) d x

\int_{0}^{1} 2 x - 2 x^{2} d x

f (x) = \frac{3}{1 + x ^{2}}

What is the derivative of 9e^{-2x} ?
The derivative of 9e^{-2x} is -18e^{-2x}
What is the first derivative of 9e^{-2x} ?
The first derivative of 9e^{-2x} is -18e^{-2x}