What is the tangent of f(x)=6tan(x),\at x= pi/3 ?

The tangent of f(x)=6tan(x),\at x= pi/3 is y=24x+6sqrt(3)-8pi

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tangent of f(x)=6tan(x),\at x= pi/3

tangent of

f (x) = 6 tan (x), at x = \frac{π}{3}

y = 24 x + 63 - 8 π

Solution steps

Find the tangent point:

(\frac{π}{3}, 63)

Find the slope of

f (x) = 6 tan (x) : \frac{df ( x )}{d x} = 6 sec^{2} (x)

Compute the slope of

f (x) = 6 tan (x)

x = \frac{π}{3} : m = 24

Find the line with slope m=

24

and passing through

(\frac{π}{3}, 63) : y = 24 x + 63 - 8 π

y = 24 x + 63 - 8 π

\frac{\partial}{\partial x} (2 x - 1)

\int x y + 1 d y

\frac{1}{( t + 1 ) ^{2}}

\int \frac{x + 4}{2 x + 3} d x

y^{^{''}} + y = e^{x} sin (x)

What is the tangent of f(x)=6tan(x),\at x= pi/3 ?
The tangent of f(x)=6tan(x),\at x= pi/3 is y=24x+6sqrt(3)-8pi