What is the derivative of (x^2+3x^2) ?

The derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)

What is the first derivative of (x^2+3x^2) ?

The first derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)

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\frac{d}{d x} ((x^{2} + 3 x)^{2})

2 (x^{2} + 3 x) (2 x + 3)

Solution steps

\frac{d}{d x} ((x^{2} + 3 x)^{2})

Apply the chain rule:

2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

= 2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= 2 (x^{2} + 3 x) (2 x + 3)

y = 5 x, y = 2 x - 5, y = 0

x \to 4 lim (6 x^{2} - 10)

y^{^{'}} = x y + x - 2 y - 2

n = 2 \sum \infty ln (1 - \frac{1}{n ^{2}})

y = \frac{x ^{2}}{x - 8}, (2, \frac{2}{5})

What is the derivative of (x^2+3x^2) ?
The derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)
What is the first derivative of (x^2+3x^2) ?
The first derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)