What is the integral from 1 to x of 1/x ?

The integral from 1 to x of 1/x is ln|x|

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integral from 1 to x of 1/x

\int_{1}^{x} \frac{1}{x} d x

ln ∣ x ∣

Solution steps

\int_{1}^{x} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{x}

Compute the boundaries:

ln ∣ x ∣

= ln ∣ x ∣

\int 4 sin^{2} (π x) cos^{5} (π x) d x

\int_{0}^{1} x \cdot e^{x^{2}} d x

\int_{0}^{1} (2 x^{2} - 1) d x

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{^{'}} = 0

\frac{d}{d x} (\frac{e ^{4 x}}{ln ( 6 x )})

What is the integral from 1 to x of 1/x ?
The integral from 1 to x of 1/x is ln|x|