What is the tangent of f(x)=4x(x^2-4x+5)^9,\at x=2 ?

The tangent of f(x)=4x(x^2-4x+5)^9,\at x=2 is y=4x

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tangent of f(x)=4x(x^2-4x+5)^9,\at x=2

tangent of

f (x) = 4 x (x^{2} - 4 x + 5)^{9}, at x = 2

y = 4 x

Solution steps

Find the tangent point:

(2, 8)

Find the slope of

f (x) = 4 x (x^{2} - 4 x + 5)^{9} : \frac{df ( x )}{d x} = 4 ((x^{2} - 4 x + 5)^{9} + 9 x (x^{2} - 4 x + 5)^{8} (2 x - 4))

Compute the slope of

f (x) = 4 x (x^{2} - 4 x + 5)^{9}

x = 2 : m = 4

Find the line with slope m=

4

and passing through

(2, 8) : y = 4 x

y = 4 x

\frac{d}{d x} (9 e^{- 4 x})

y^{3} \frac{d y}{d x} + x^{3} = 0

\frac{\partial}{\partial y} (x^{2} - 4 x y - 2 y^{2})

\int (3 x^{2} - 6 x + 3) d x

\int_{0}^{\frac{1}{4}} 5 arcsin (4 x) d x

What is the tangent of f(x)=4x(x^2-4x+5)^9,\at x=2 ?
The tangent of f(x)=4x(x^2-4x+5)^9,\at x=2 is y=4x