What is the solution for y^'=(e^{t-y})/(1+e^t) ?

The solution for y^'=(e^{t-y})/(1+e^t) is y=ln(ln(1+e^t)+c_{1})

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y^'=(e^{t-y})/(1+e^t)

y^{^{'}} = \frac{e ^{t - y}}{1 + e ^{t}}

y = ln (ln (1 + e^{t}) + c_{1})

Solution steps

y^{'} (t) = \frac{e ^{t - y}}{1 + e ^{t}}

Solve separable ODE:

y = ln (ln (1 + e^{t}) + c_{1})

y = ln (ln (1 + e^{t}) + c_{1})

x \to \infty lim (e^{- π})

\frac{d}{d x} (\frac{3 - x ^{2}}{2 x + 2})

\int x^{2} e^{- \frac{x}{4}} d x

\frac{d}{d x} (cos^{2} (8 x))

What is the solution for y^'=(e^{t-y})/(1+e^t) ?
The solution for y^'=(e^{t-y})/(1+e^t) is y=ln(ln(1+e^t)+c_{1})