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Popular >

x^'+4x=0

Solution

x^{^{'}} + 4 x = 0

Solution

x = e^{- 4 t + c_{1}}

Solution steps

x^{'} (t) + 4 x = 0

Solve separable ODE:

x = e^{- 4 t + c_{1}}

x = e^{- 4 t + c_{1}}

Popular Examples

integral of e^{-22x}

\int e^{- 22 x} d x

derivative of y=108-90e^{-0.4t}derivative of

y = 108 - 90 e^{- 0.4 t}

f(x)=x^2e^x-2xe^x+8e^x

f (x) = x^{2} e^{x} - 2 x e^{x} + 8 e^{x}

limit as h approaches 0 of ((1+h)-(1))/h

h \to 0 lim (\frac{( 1 + h ) - ( 1 )}{h})

\frac{d y}{d x} = - y - 8

Frequently Asked Questions (FAQ)

What is the solution for x^'+4x=0 ?
The solution for x^'+4x=0 is x=e^{-4t+c_{1}}