What is the sum from n=1 to infinity of (2x)^n ?

The sum from n=1 to infinity of (2x)^n is Interval of convergence is-1/2 <x< 1/2

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sum from n=1 to infinity of (2x)^n

n = 1 \sum \infty (2 x)^{n}

Interval of convergence is - \frac{1}{2} < x < \frac{1}{2}

Solution steps

n = 1 \sum \infty (2 x)^{n}

Use the Root Test to compute the convergence interval

Interval of convergence is - \frac{1}{2} < x < \frac{1}{2}

\frac{\partial}{\partial x} (y^{2} - 3 x^{3})

4 + t^{6}

f (x) = - 5 x

y^{^{'''}} - 7 y^{^{'}} + 6 y = e^{3 x}

\frac{d}{d x} (1 - x^{2} + y^{2})

What is the sum from n=1 to infinity of (2x)^n ?
The sum from n=1 to infinity of (2x)^n is Interval of convergence is-1/2 <x< 1/2