What is the derivative of x^3+7e^x ?

The derivative of x^3+7e^x is 3x^2+7e^x

What is the first derivative of x^3+7e^x ?

The first derivative of x^3+7e^x is 3x^2+7e^x

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derivative of

x^{3} + 7 e^{x}

3 x^{2} + 7 e^{x}

Solution steps

\frac{d}{d x} (x^{3} + 7 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (7 e^{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

= 3 x^{2} + 7 e^{x}

\frac{x d y}{d x} = y^{2} - 4

\frac{d y}{d x} = (\frac{y}{x} + \frac{1}{4})^{2}

y = (f (x))^{2}, at x = 0

4500 (1 - \frac{1}{50} t)^{2}

\int \frac{2 x ^{2} + 8 x - 8}{x - 4} d x

What is the derivative of x^3+7e^x ?
The derivative of x^3+7e^x is 3x^2+7e^x
What is the first derivative of x^3+7e^x ?
The first derivative of x^3+7e^x is 3x^2+7e^x