What is the solution for (xdy)/(dx)=y^2-4 ?

The solution for (xdy)/(dx)=y^2-4 is y=(2e^{4c_{1}})/(x^4-e^{4c_{1)}}+(2x^4)/(x^4-e^{4c_{1)}}

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(xdy)/(dx)=y^2-4

\frac{x d y}{d x} = y^{2} - 4

y = \frac{2 e ^{4 c_{1}}}{x ^{4} - e ^{4 c_{1}}} + \frac{2 x ^{4}}{x ^{4} - e ^{4 c_{1}}}

Solution steps

\frac{x d y}{d x} = y^{2} - 4

Solve separable ODE:

y = \frac{2 e ^{4 c_{1}}}{x ^{4} - e ^{4 c_{1}}} + \frac{2 x ^{4}}{x ^{4} - e ^{4 c_{1}}}

y = \frac{2 e ^{4 c_{1}}}{x ^{4} - e ^{4 c_{1}}} + \frac{2 x ^{4}}{x ^{4} - e ^{4 c_{1}}}

\frac{d y}{d x} = (\frac{y}{x} + \frac{1}{4})^{2}

y = (f (x))^{2}, at x = 0

4500 (1 - \frac{1}{50} t)^{2}

\int \frac{2 x ^{2} + 8 x - 8}{x - 4} d x

f (x) = \frac{( x - 2 ) ^{5}}{16}

What is the solution for (xdy)/(dx)=y^2-4 ?
The solution for (xdy)/(dx)=y^2-4 is y=(2e^{4c_{1}})/(x^4-e^{4c_{1)}}+(2x^4)/(x^4-e^{4c_{1)}}