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Popular >

tangent of y=x^2+x,(0,0)

Solution

tangent of

y = x^{2} + x, (0, 0)

Solution

y = x

Solution steps

Find the slope of

y = x^{2} + x : \frac{d y}{d x} = 2 x + 1

Compute the slope of

y = x^{2} + x

at

(0, 0) : m = 1

Find the line with slope m=

1

and passing through

(0, 0) : y = x

y = x

Popular Examples

integral from 0 to 1 of (22)/(4y-1)

\int_{0}^{1} \frac{22}{4 y - 1} d y

derivative of (x^2-1/(x^2-4))

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} - 4})

integral of (cos(y))/(sin^2(y))

\int \frac{cos ( y )}{sin ^{2} ( y )} d y

(\partial)/(\partial x)(5e^y)

\frac{\partial}{\partial x} (5 e^{y})

sum from n=1 to infinity of 1/((n^2+8n))

n = 1 \sum \infty \frac{1}{( n ^{2} + 8 n )}

Frequently Asked Questions (FAQ)

What is the tangent of y=x^2+x,(0,0) ?
The tangent of y=x^2+x,(0,0) is y=x