What is the integral of (cos(y))/(sin^2(y)) ?

The integral of (cos(y))/(sin^2(y)) is -csc(y)+C

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integral of (cos(y))/(sin^2(y))

\int \frac{cos ( y )}{sin ^{2} ( y )} d y

- csc (y) + C

Solution steps

\int \frac{cos ( y )}{sin ^{2} ( y )} d y

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = sin (y)

= - \frac{1}{sin ( y )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= - csc (y)

Add a constant to the solution

= - csc (y) + C

\frac{\partial}{\partial x} (5 e^{y})

n = 1 \sum \infty \frac{1}{( n ^{2} + 8 n )}

\int \frac{1}{x ( 1 + ln ( x ) ) ( 2 + ln ( x ) )} d x

\int \frac{8 + 5 x}{1 + x ^{2}} d x

x \to - 10 - lim (\frac{1}{x + 10})

What is the integral of (cos(y))/(sin^2(y)) ?
The integral of (cos(y))/(sin^2(y)) is -csc(y)+C