What is the derivative of g(t)=2t^{-3/4} ?

The derivative of g(t)=2t^{-3/4} is -3/(2t^{7/4)}

What is the first derivative of g(t)=2t^{-3/4} ?

The first derivative of g(t)=2t^{-3/4} is -3/(2t^{7/4)}

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derivative of

g (t) = 2 t^{- \frac{3}{4}}

- \frac{3}{2 t ^{\frac{7}{4}}}

Solution steps

\frac{d}{d t} (2 t^{- \frac{3}{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t^{- \frac{3}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- \frac{3}{4} t^{- \frac{3}{4} - 1})

Simplify

2 (- \frac{3}{4} t^{- \frac{3}{4} - 1}) : - \frac{3}{2 t ^{\frac{7}{4}}}

= - \frac{3}{2 t ^{\frac{7}{4}}}

\frac{\partial}{\partial x} (e^{x} + yz)

3 x y^{^{'}} - y (x + 1) + 7 y^{4} = 0

\frac{d y}{d x}, x^{2} + y^{2} = 24

cos^{2} (t)

tan^{6} (x)

What is the derivative of g(t)=2t^{-3/4} ?
The derivative of g(t)=2t^{-3/4} is -3/(2t^{7/4)}
What is the first derivative of g(t)=2t^{-3/4} ?
The first derivative of g(t)=2t^{-3/4} is -3/(2t^{7/4)}