What is (\partial)/(\partial s)(1+st) ?

The answer to (\partial)/(\partial s)(1+st) is t

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(\partial)/(\partial s)(1+st)

\frac{\partial}{\partial s} (1 + s t)

t

Solution steps

\frac{\partial}{\partial s} (1 + s t)

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial s} (1) + \frac{\partial}{\partial s} (s t)

\frac{\partial}{\partial s} (1) = 0

\frac{\partial}{\partial s} (s t) = t

= 0 + t

Simplify

= t

\int \frac{11 x + 64}{x ^{2} + 13 x + 40} d x

x \to 0 lim (\frac{( x ^{2} )}{e - 1})

\frac{\partial}{\partial x} (1 - x^{2} - x - 2 y^{2} + y)

ln (2) + ln (x)

y = \frac{e ^{6 x}}{e ^{6 x} + 3}

What is (\partial)/(\partial s)(1+st) ?
The answer to (\partial)/(\partial s)(1+st) is t