What is the derivative of (3cos(x)/(1-sin(x))) ?

The derivative of (3cos(x)/(1-sin(x))) is 3/(1-sin(x))

What is the first derivative of (3cos(x)/(1-sin(x))) ?

The first derivative of (3cos(x)/(1-sin(x))) is 3/(1-sin(x))

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\frac{d}{d x} (\frac{3 cos ( x )}{1 - sin ( x )})

\frac{3}{1 - sin ( x )}

Solution steps

\frac{d}{d x} (\frac{3 cos ( x )}{1 - sin ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{cos ( x )}{1 - sin ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d}{d x} ( cos ( x ) ) ( 1 - sin ( x ) ) - \frac{d}{d x} ( 1 - sin ( x ) ) cos ( x )}{( 1 - sin ( x ) ) ^{2}}

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (1 - sin (x)) = - cos (x)

= 3 \cdot \frac{( - sin ( x ) ) ( 1 - sin ( x ) ) - ( - cos ( x ) ) cos ( x )}{( 1 - sin ( x ) ) ^{2}}

Simplify

3 \cdot \frac{( - sin ( x ) ) ( 1 - sin ( x ) ) - ( - cos ( x ) ) cos ( x )}{( 1 - sin ( x ) ) ^{2}} : \frac{3}{1 - sin ( x )}

= \frac{3}{1 - sin ( x )}

\int \frac{x ^{3} - x ^{2} + 2}{x ^{3} - 2 x ^{2} + 2 x} d x

\int_{5}^{10} \frac{8}{5 - 2 x} d x

y = \frac{1}{3} (x^{2} + 2)^{\frac{3}{2}}

sec (9 x)

\frac{d}{d x} (4.5 x + 2.4 x^{2} + 1.1 x^{3})

What is the derivative of (3cos(x)/(1-sin(x))) ?
The derivative of (3cos(x)/(1-sin(x))) is 3/(1-sin(x))
What is the first derivative of (3cos(x)/(1-sin(x))) ?
The first derivative of (3cos(x)/(1-sin(x))) is 3/(1-sin(x))