What is the derivative of 4.5x+2.4x^2+1.1x^3 ?

The derivative of 4.5x+2.4x^2+1.1x^3 is 4.5+4.8x+3.3x^2

What is the first derivative of 4.5x+2.4x^2+1.1x^3 ?

The first derivative of 4.5x+2.4x^2+1.1x^3 is 4.5+4.8x+3.3x^2

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\frac{d}{d x} (4.5 x + 2.4 x^{2} + 1.1 x^{3})

4.5 + 4.8 x + 3.3 x^{2}

Solution steps

\frac{d}{d x} (4.5 x + 2.4 x^{2} + 1.1 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4.5 x) + \frac{d}{d x} (2.4 x^{2}) + \frac{d}{d x} (1.1 x^{3})

\frac{d}{d x} (4.5 x) = 4.5

\frac{d}{d x} (2.4 x^{2}) = 4.8 x

\frac{d}{d x} (1.1 x^{3}) = 3.3 x^{2}

= 4.5 + 4.8 x + 3.3 x^{2}

\frac{d}{d x} (ln (x y))

\frac{d}{d w} ((ln (w))^{(2 w)})

\int_{0}^{π} 4 \cdot sin (x) d x

\int \frac{1}{( 1 + 2 x ) ^{2}} d x

\int 1 + e^{x^{2}} d x

What is the derivative of 4.5x+2.4x^2+1.1x^3 ?
The derivative of 4.5x+2.4x^2+1.1x^3 is 4.5+4.8x+3.3x^2
What is the first derivative of 4.5x+2.4x^2+1.1x^3 ?
The first derivative of 4.5x+2.4x^2+1.1x^3 is 4.5+4.8x+3.3x^2