What is the tangent of (ln(x^2-10x-10)),\at x=11 ?

The tangent of (ln(x^2-10x-10)),\at x=11 is y=12x-132

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tangent of (ln(x^2-10x-10)),\at x=11

tangent of

(ln (x^{2} - 10 x - 10)), at x = 11

y = 12 x - 132

Solution steps

Find the tangent point:

(11, 0)

Find the slope of

y = ln (x^{2} - 10 x - 10) : \frac{d y}{d x} = \frac{2 x - 10}{x ^{2} - 10 x - 10}

Compute the slope of

y = ln (x^{2} - 10 x - 10)

x = 11 : m = 12

Find the line with slope m=

12

and passing through

(11, 0) : y = 12 x - 132

y = 12 x - 132

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What is the tangent of (ln(x^2-10x-10)),\at x=11 ?
The tangent of (ln(x^2-10x-10)),\at x=11 is y=12x-132