What is the integral of e^{2x+2} ?

The integral of e^{2x+2} is 1/2 e^{2x+2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{2x+2}

\int e^{2 x + 2} d x

\frac{1}{2} e^{2 x + 2} + C

Solution steps

\int e^{2 x + 2} d x

Apply u-substitution

: \int e^{u} \frac{1}{2} d u

= \int e^{u} \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{2} e^{u}

Substitute back

u = 2 x + 2

= \frac{1}{2} e^{2 x + 2}

Add a constant to the solution

= \frac{1}{2} e^{2 x + 2} + C

\int x^{\frac{3}{4}} + 6 d x

y^{^{'''}} - 6 y^{^{''}} - 7 y^{^{'}} = 0

\int t^{3} d t

\int (\frac{( x ^{3} - 3 x ^{2} + 3 )}{( x - 3 )}) d x

x \to 0 lim (\frac{( - 6 + x ) ^{2} - 36}{x})