What is the derivative of y=sqrt(7x+5) ?

The derivative of y=sqrt(7x+5) is 7/(2sqrt(7x+5))

What is the first derivative of y=sqrt(7x+5) ?

The first derivative of y=sqrt(7x+5) is 7/(2sqrt(7x+5))

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derivative of

y = 7 x + 5

\frac{7}{2 7 x + 5}

Solution steps

\frac{d}{d x} (7 x + 5)

Apply the chain rule:

\frac{1}{2 7 x + 5} \frac{d}{d x} (7 x + 5)

= \frac{1}{2 7 x + 5} \frac{d}{d x} (7 x + 5)

\frac{d}{d x} (7 x + 5) = 7

= \frac{1}{2 7 x + 5} \cdot 7

Simplify

\frac{1}{2 7 x + 5} \cdot 7 : \frac{7}{2 7 x + 5}

= \frac{7}{2 7 x + 5}

9 (x^{3} - x)^{4}

\frac{\partial}{\partial x} (5 sin (2 (5 x + 6 y)))

\int x^{2} \cdot x^{3} + 1 d x

x \to 2 lim (\frac{x ^{3} - 1}{x - 1})

\frac{d}{d x} (1 + ln (x))

What is the derivative of y=sqrt(7x+5) ?
The derivative of y=sqrt(7x+5) is 7/(2sqrt(7x+5))
What is the first derivative of y=sqrt(7x+5) ?
The first derivative of y=sqrt(7x+5) is 7/(2sqrt(7x+5))