What is the derivative of f(x)=(x^2+3x)/6 ?

The derivative of f(x)=(x^2+3x)/6 is 1/6 (2x+3)

What is the first derivative of f(x)=(x^2+3x)/6 ?

The first derivative of f(x)=(x^2+3x)/6 is 1/6 (2x+3)

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derivative of

f (x) = \frac{x ^{2} + 3 x}{6}

\frac{1}{6} (2 x + 3)

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 3 x}{6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{d}{d x} (x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{6} (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= \frac{1}{6} (2 x + 3)

\int (6 x^{6} - 6 x^{5} - 4 x^{3} + 2) d x

ln (cos (x)), 0

\frac{d}{d x} (\frac{9}{x ^{2} + 5})

\frac{d}{d x} ((x + 5)^{\frac{2}{3}})

\frac{d y}{d x} = (x + y - 2)^{2}

What is the derivative of f(x)=(x^2+3x)/6 ?
The derivative of f(x)=(x^2+3x)/6 is 1/6 (2x+3)
What is the first derivative of f(x)=(x^2+3x)/6 ?
The first derivative of f(x)=(x^2+3x)/6 is 1/6 (2x+3)